QuizSagar
4 years ago Like 232906
Questions 823
Contests 7
12/4 = __
- 12
- 3
- 4
- -4
- 3
Clear All
(12/4)= 3
when we divide 12 by 4 then result will be 3
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-12/4 = __
- 12
- 3
- 4
- -3
- -3
Clear All
12/4=-(12/4)= -(3)=3
when we divide 12 by 4 then result will be 3
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-12/-4 = __
- 12
- 3
- 4
- -3
- 3
Clear All
-12/-4=12/4= 3
when we divide 12 by 4 then result will be 3
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-12/-4 + 2= __
- 3
- 5
- 4
- -3
- 5
Clear All
-12/-4=12/4= 3
Now, (-12/-4) + 2 = 3+2 =5
when we divide -12 by -4 then result will be 3 and
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-12/-4 + 2/4= __
- -10/4
- 14/4
- -14/4
- 10/4
- 14/4
Clear All
(-12/-4) +(2/4)
=(12/4)+(2/4)
= (12+2)/4
=14/4
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Reciprocal of "a" is
- a
- 1/a
- -a
- -1/a
- 1/a
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Writes the elements 1,2,2,3 in Roster form?
- {1,2,3}
- {1,2,2,3}
- [1,2,3]
- (1,2,3)
- {1,2,3}
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A set is well defined Collection of "Distinct object", set is represented by {}. SO Only option 1 is correct answer.
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Write the set A = {1, 2, 3,. . . } in set-builder form.
- A={x | x is a positive integer}
- A={x | (x=1) v (x=2) v (x=3)}
- A={x | x is an integer}
- A={x | x is a natural number}
- A={x | x is a positive integer}
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A set is well defined Collection of "Distinct object", set is represented by {}. SO Only option 1 is correct answer.
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Write the set A = {1, 3, 5,. . . } in set-builder form.
- A={x | x is a even positive integer}
- A={x | (x=1) v (x=3) v (x=5)}
- A={x | x is an odd positive integer
- A={x | x is a natural number}
- A={x | x is an odd positive integer
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Subset of set A of cardinality 2 is ____.Where Set A = {1,2,3}?
- {1,2},{2,1}
- {1, 2} , {2,1} & {2,3}
- {1,2},{2,3} & {3,2}
- {1,2},{2,3} & {1,3}
- {1,2},{2,3} & {1,3}
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Cardinality of a set A is total number of elements in set A.
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